{"id":18526,"date":"2024-07-12T15:24:47","date_gmt":"2024-07-12T08:24:47","guid":{"rendered":"https:\/\/soicau3092.minhngocxoso.com\/?p=18526"},"modified":"2024-07-12T15:24:47","modified_gmt":"2024-07-12T08:24:47","slug":"cach-tinh-phuong-phap-xac-suat-lo-de-xo-so-ngay-le-chan","status":"publish","type":"post","link":"https:\/\/bachthude247.com\/cach-tinh-phuong-phap-xac-suat-lo-de-xo-so-ngay-le-chan\/","title":{"rendered":"c\u00e1ch t\u00ednh ph\u01b0\u01a1ng ph\u00e1p x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1, x\u1ed5 s\u1ed1 ng\u00e0y l\u1ebb ch\u1eb5n"},"content":{"rendered":"
C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1<\/strong>\u00a0b\u1eb1ng c\u00f4ng th\u1ee9c v\u00e0 ph\u01b0\u01a1ng ph\u00e1p n\u00e0o? T\u1ed5ng h\u1ee3p chi ti\u1ebft nh\u1eefng b\u01b0\u1edbc h\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 \u0111\u1ec1, x\u1ed5 s\u1ed1 ch\u00ednh x\u00e1c nh\u1ea5t, t\u1ef7 l\u1ec7 tr\u00fang s\u1ed1 h\u00f4m nay l\u00e0 cao nh\u1ea5t m\u00e0 kh\u00f4ng c\u1ea7n d\u1ef1a v\u00e0o ph\u1ea7n m\u1ec1m t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 ra sao? H\u00e3y c\u00f9ng\u00a0Tin t\u1ee9c l\u00f4 \u0111\u1ec1<\/strong>\u00a0tham kh\u1ea3o ngay t\u1ea1i b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y nh\u00e9!<\/p>\n V\u1edbi anh em l\u00f4 \u0111\u1ec1 th\u1ee7 l\u00e2u n\u0103m th\u00ec c\u00f3 r\u1ea5t nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p t\u00ednh s\u1ed1 l\u00f4 \u0111\u1ec1 ri\u00eang v\u1edbi kh\u1ea3 n\u0103ng tr\u00fang l\u00e0 r\u1ea5t cao. Th\u1ebf nh\u01b0ng v\u1edbi c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 sau \u0111\u00e2y \u0111\u01b0\u1ee3c ch\u00fang t\u00f4i chia s\u1ebb th\u00ec d\u00f9 l\u00e0 anh em m\u1edbi ch\u01a1i c\u0169ng c\u00f3 th\u1ec3 mang l\u1ea1i hi\u1ec7u qu\u1ea3 ch\u01a1i l\u00e0 cao nh\u1ea5t, t\u1ef7 l\u1ec7 d\u1ef1 \u0111o\u00e1n tr\u00fang l\u1edbn. V\u1eady x\u00e1c su\u1ea5t \u0111\u1ec3 tr\u00fang \u0111\u1ec1 1 con v\u00e0 tr\u00fang \u0111\u1ec1 3 c\u00e0ng c\u00f3 g\u00ec kh\u00e1c nhau v\u00e0 v\u1edbi t\u1ef7 l\u1ec7 bao nhi\u00eau?<\/p>\n H\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 tr\u00fang s\u1ed1 nh\u01b0 th\u1ebf n\u00e0o?<\/em><\/p>\n Nh\u01b0 anh em \u0111\u00e3 bi\u1ebft th\u00ec \u0111\u1ec1 \u0111\u01b0\u1ee3c hi\u1ec3u \u0111\u01a1n gi\u1ea3n l\u00e0 2 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t, n\u00ean s\u1ebd ch\u1ec9 c\u00f3 duy nh\u1ea5t m\u1ed9t con \u0111\u1ec1. Ch\u00ednh v\u00ec v\u1eady th\u00ec x\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 l\u00e0 1\/100.<\/p>\n Ph\u01b0\u01a1ng ph\u00e1p c\u00e1ch \u0111\u1ec3 t\u00ednh x\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 3 c\u00e0ng l\u00e0 r\u1ea5t ph\u1ee9c t\u1ea1p, v\u1eady n\u00ean nhi\u1ec1u anh em th\u01b0\u1eddng chia s\u1ebb r\u1eb1ng x\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 3 c\u00e0ng \u0111\u01b0\u1ee3c t\u00ednh b\u1edfi c\u00e1c ph\u1ea7n m\u1ec1m t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 v\u1edbi t\u1ef7 l\u1ec7 l\u00e0: 1\/1000 t\u1ee9c l\u00e0 0.1%.<\/p>\n D\u01b0\u1edbi \u0111\u00e2y ch\u00fang t\u00f4i s\u1ebd t\u1ed5ng h\u1ee3p l\u1ea1i v\u00e0 chia s\u1ebb t\u1edbi anh em m\u1ed9t s\u1ed1 h\u01b0\u1edbng d\u1eabn chi ti\u1ebft v\u1ec1 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang m\u1ed9t s\u1ed1 lo\u1ea1i l\u00f4 nh\u01b0: tr\u00fang 1 l\u00f4, x\u00e1c su\u1ea5t \u0103n nhi\u1ec1u l\u00f4, tr\u00fang l\u00f4 3 c\u00e0ng, l\u00f4 xi\u00ean \u0111\u00f4i,\u2026 Gi\u00fap ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 nhanh ch\u00f3ng t\u00ednh \u0111\u01b0\u1ee3c x\u00e1c su\u1ea5t t\u1ef7 l\u1ec7 tr\u00fang h\u00f4m nay c\u1ee7a m\u00ecnh v\u1edbi con l\u00f4 \u0111\u00e3 c\u01b0\u1ee3c.<\/p>\n X\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc c\u00f3 27 gi\u1ea3i x\u1ed5 s\u1ed1, v\u00ec th\u1ebf ch\u00fang ta c\u00f3 27 c\u01a1 h\u1ed9i \u0111o\u00e1n tr\u00fang l\u00f4, x\u1ed5 s\u1ed1 mi\u1ec1n Nam, mi\u1ec1n Trung c\u00f3 18 gi\u1ea3i n\u00ean ch\u00fang ta c\u0169ng c\u00f3 18 c\u01a1 h\u1ed9i \u0111o\u00e1n l\u00f4. Tuy nhi\u00ean x\u00e1c su\u1ea5t c\u1ee7a n\u00f3 c\u00f3 ph\u1ea3i th\u1eadt nh\u01b0 v\u1eady kh\u00f4ng? Ta c\u00f9ng t\u00ednh th\u1eed x\u00e1c su\u1ea5t tr\u00fang l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc nh\u01b0 sau:<\/p>\n T\u1ef7 l\u1ec7 th\u1eafng c\u1ee7a 27 gi\u1ea3i XSMB l\u00e0 100%, t\u1ef7 l\u1ec7 tr\u01b0\u1ee3t 1 gi\u1ea3i l\u00e0 99%. Gi\u1ea3 s\u1eed c\u00e1c gi\u1ea3i c\u00f3 x\u00e1c su\u1ea5t tr\u01b0\u1ee3t nh\u01b0 nhau, ta c\u00f3:<\/p>\n + Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t: x\u00e1c su\u1ea5t tr\u01b0\u1ee3t l\u00e0 99%<\/p>\n + Gi\u1ea3i nh\u1ea5t: x\u00e1c su\u1ea5t tr\u01b0\u1ee3t l\u00e0 99% x 99%<\/p>\n + Gi\u1ea3i nh\u1ea5t: x\u00e1c su\u1ea5t tr\u01b0\u1ee3t l\u00e0 99% x 99%<\/p>\n + Gi\u1ea3i 27: x\u00e1c su\u1ea5t tr\u01b0\u1ee3t l\u00e0 (99%)27 = 0,7623<\/p>\n Nh\u01b0 v\u1eady ta c\u00f3 c\u1ee9 quay \u0111\u01b0\u1ee3c m\u1ed9t gi\u1ea3i th\u00ec ch\u00fang ta s\u1ebd nh\u1eadn th\u00eam 1 s\u1ed1 99%, t\u1eeb \u0111\u00f3 ta c\u00f3 t\u1ef7 l\u1ec7 soi c\u1ea7u x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc tr\u00fang l\u00f4 theo t\u00ednh to\u00e1n \u0111\u00f3 l\u00e0: 1 \u2013 0,7623 = 0,2376 t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi 23,76%.<\/p>\n T\u1eeb x\u00e1c su\u1ea5t tr\u00fang 1 l\u00f4, ta c\u00f3 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang nhi\u1ec1u l\u00f4 nh\u01b0 sau:<\/p>\n + X\u00e1c su\u1ea5t tr\u00fang 2 l\u00f4 l\u00e0: 1 \u2013 (98%)27 ~ 0,42 t\u1ee9c l\u00e0 42%<\/p>\n + X\u00e1c su\u1ea5t tr\u00fang 3 l\u00f4 l\u00e0: 1 \u2013 (97%)27 ~ 0,56 t\u1ee9c l\u00e0 56%<\/p>\n + X\u00e1c su\u1ea5t tr\u00fang 4 l\u00f4 l\u00e0: 1 \u2013 (96%)27 ~ 0,67 t\u1ee9c l\u00e0 67%<\/p>\n Nh\u01b0 v\u1eady, c\u00f4ng th\u1ee9c t\u1ed5ng qu\u00e1t t\u00ednh x\u00e1c su\u1ea5t tr\u00fang n l\u00f4 l\u00e0 1 \u2013 [(100 \u2013 n)%]27<\/p>\n X\u00e1c su\u1ea5t tr\u00fang l\u00f4 3 c\u00e0ng = 1 \u2013 x\u00e1c su\u1ea5t tr\u01b0\u1ee3t l\u00f4 3 c\u00e0ng = 1 \u2013 0.99927= 2,67%<\/p>\n Tham kh\u1ea3o:\u00a0Soi c\u1ea7u ch\u1ed1t s\u1ed1 3 c\u00e0ng vip mi\u1ec5n ph\u00ed \u2013 3 c\u00e0ng \u0103n bao nhi\u00eau<\/strong><\/p>\n T\u00ednh x\u00e1c su\u1ea5t tr\u01b0\u1ee3t 1 con l\u00f4 l\u00e0 99%<\/p>\n T\u00ednh x\u00e1c su\u1ea5t tr\u01b0\u1ee3t 2 con l\u00f4 l\u00e0 (99%)2~ 98%<\/p>\n T\u00ednh x\u00e1c su\u1ea5t tr\u01b0\u1ee3t 3 con l\u00f4 l\u00e0 (99%)3 ~ 97%<\/p>\n X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 hai con (tr\u01b0\u1ee3t h\u1ebft): (98%)27 ~ 57,9%<\/p>\n X\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 \u0111\u00fang 1 con (tr\u01b0\u1ee3t h\u1ebft, tr\u00fang 1): 2 x 76,2% x 23,7%\u00a0 ~ 36,1%<\/p>\n X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 2: 57,9% + 36,1% ~ 94%<\/p>\n Nh\u01b0 v\u1eady x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2 = 100% \u2013 94% cho ra t\u1ef7 l\u1ec7 ~ 6%.<\/p>\n Xem th\u00eam:\u00a0Soi c\u1ea7u l\u00f4 xi\u00ean mi\u1ec1n B\u1eafc h\u00f4m nay mi\u1ec5n ph\u00ed<\/strong><\/p>\n H\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 x\u1ed5 s\u1ed1 h\u00f4m nay hi\u1ec7u qu\u1ea3 nh\u1ea5t<\/em><\/p>\n Th\u00f4ng th\u01b0\u1eddng th\u00ec ch\u00fang ta hay nu\u00f4i m\u1ed9t con l\u00f4 n\u00e0o \u0111\u00f3 trong n ng\u00e0y, nh\u01b0 v\u1eady l\u00e0m sao \u0111\u1ec3 t\u00ednh \u0111\u01b0\u1ee3c x\u00e1c su\u1ea5t l\u00f4 \u0111\u00f3 v\u1ec1 t\u1ef7 l\u1ec7 l\u00e0 bao nhi\u00eau trong n ng\u00e0y?<\/p>\n D\u1ef1a v\u00e0o logarit trong to\u00e1n h\u1ecdc ta s\u1ebd c\u00f3 c\u00f4ng th\u1ee9c t\u00ednh to\u00e1n sau:<\/p>\n \u2013 Gi\u1ea3 s\u1eed A l\u00e0 bi\u1ebfn c\u1ed1 trong n ng\u00e0y, ta kh\u00f4ng tr\u00fang l\u1ea7n n\u00e0o<\/p>\n B l\u00e0 bi\u1ebfn c\u1ed1 ta tr\u00fang \u00edt nh\u1ea5t 1 l\u1ea7n<\/p>\n X\u00e1c su\u1ea5t \u0111\u1ec3 ta tr\u01b0\u1ee3t c\u1ea3 27 con l\u00f4 trong d\u00e0n l\u00f4 c\u1ee7a m\u1ed9t ng\u00e0y l\u00e0: (99%)27<\/p>\n P(A) = (99%)27n<\/p>\n P(B) = 1\u2212P(A) = 1 \u2212 (99%)27n<\/p>\n P(B) > m \u21d4 (99%)27n < 1 \u2212 m \u21d4 n > log0,99(1 \u2212 m)\/27<\/p>\n V\u1edbi m = 0,9999 (t\u1ef7 l\u1ec7 99,99%), ta c\u00f3: n > 33,9, c\u00f3 ngh\u0129a l\u00e0 trong v\u00f2ng 34 ng\u00e0y th\u00ec x\u00e1c su\u1ea5t ta \u0111\u00e1nh tr\u00fang \u00edt nh\u1ea5t 1 l\u1ea7n l\u00e0 99,99%, khi \u0111\u00f3 trong v\u00f2ng 34 ng\u00e0y th\u00ec l\u00f4 b\u1ea1n nu\u00f4i c\u00f3 t\u1ef7 l\u1ec7 th\u1eafng c\u1ef1c \u0111\u1ea1i.<\/p>\n Hy v\u1ecdng r\u1eb1ng v\u1edbi nh\u1eefng chia s\u1ebb c\u1ee7a ch\u00fang t\u00f4i v\u1ec1 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1, x\u1ed5 s\u1ed1 th\u00ec anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng \u0111\u1ec3 t\u00ednh to\u00e1n loto, s\u1ed1 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 nh\u1ea5t, mang t\u1edbi k\u1ebft qu\u1ea3 tr\u00fang s\u1ed1 cao nh\u1ea5t khi ch\u01a1i nh\u00e9!<\/p>\n<\/div>\n<\/div>\nC\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 chu\u1ea9n b\u1eb1ng c\u00e1ch n\u00e0o?<\/strong><\/h2>\n
<\/p>\n
T\u00ednh x\u00e1c su\u1ea5t s\u1ed1 \u0111\u1ec1 tr\u00fang 1 con<\/strong><\/h3>\n
X\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 3 c\u00e0ng<\/strong><\/h3>\n
H\u01b0\u1edbng d\u1eabn t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 chu\u1ea9n nh\u1ea5t<\/strong><\/h2>\n
T\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 tr\u00fang 1 l\u00f4<\/strong><\/h3>\n
<\/p>\n
C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 \u0103n nhi\u1ec1u l\u00f4<\/strong><\/h3>\n
C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 3 c\u00e0ng<\/strong><\/h3>\n
T\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean \u0111\u00f4i<\/strong><\/h3>\n
C\u00e1ch nu\u00f4i l\u00f4 theo x\u00e1c su\u1ea5t ch\u00ednh x\u00e1c nh\u1ea5t<\/strong><\/h2>\n
<\/p>\n
chuy\u00ean gia ch\u1ed1t s\u1ed1 v\u00edp si\u00eau h\u00f3t<\/strong><\/span><\/h3>\n