Nu\u00f4i l\u00f4 k\u00e9p khung ng\u00e0y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i mang l\u1ea1i hi\u1ec7u qu\u1ea3 \u0111ang \u0111\u01b0\u1ee3c c\u00e1c d\u00e2n ch\u01a1i l\u00f4 \u0111\u1ec1 \u00e1p d\u1ee5ng nhi\u1ec1u. Tuy nhi\u00ean l\u00e0 th\u1ebf n\u00e0o \u0111\u1ec3 soi \u0111\u01b0\u1ee3c c\u1ea7u, t\u00ecm \u0111\u01b0\u1ee3c nh\u1eefng con s\u1ed1 may m\u1eafn \u0111\u1ed3ng th\u1eddi v\u00e0o ti\u1ec1n th\u1ebf n\u00e0o? N\u1ebfu ch\u01b0a bi\u1ebft v\u1ec1 n\u00f3, h\u00e3y t\u00ecm hi\u1ec3u ngay!<\/p>\n
Nu\u00f4i l\u00f4 \u0111\u1ec1 hay soi c\u1ea7u l\u00e0 nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p th\u01b0\u1eddng \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi s\u1eed d\u1ee5ng \u0111\u1ec3 ch\u1ecdn ra nh\u1eefng con s\u1ed1 may m\u1eafn.\u00a0Nu\u00f4i l\u00f4 k\u00e9p theo khung\u00a0ng\u00e0y\u00a0(2 ng\u00e0y, 3 ng\u00e0y, 5 ng\u00e0y v\u00e0 7 ng\u00e0y)\u00a0\u0111\u01b0\u1ee3c xem l\u00e0 m\u1ed9t trong c\u00e1c\u00a0chi\u1ebfn thu\u1eadt hay nh\u1ea5t\u00a0\u0111\u01b0\u1ee3c c\u00e1c d\u00e2n ch\u01a1i l\u00f4 \u0111\u1ec1 g\u1ea1o c\u1ed9i \u00e1p d\u1ee5ng. Trong b\u00e0i vi\u1ebft n\u00e0y, ad s\u1ebd chia s\u1ebb t\u1edbi b\u1ea1n \u0111\u1ecdc nh\u1eefng th\u00f4ng tin ch\u00ednh x\u00e1c nh\u1ea5t li\u00ean quan t\u1edbi l\u00f4 k\u00e9p khung 2 ng\u00e0y v\u00e0 c\u00e1ch nu\u00f4i v\u1edbi t\u1ef7 l\u1ec7 \u0103n cao nh\u1ea5t.<\/p>\n
B\u00e0i vi\u1ebft h\u01b0\u1edbng d\u1eabn h\u1ed9i vi\u00ean \u0111\u00e3 c\u00f3 nh\u1eefng hi\u1ec3u bi\u1ebft nh\u1ea5t \u0111\u1ecbnh v\u1ec1 k\u00e9p, n\u1ebfu ch\u01b0a bi\u1ebft k\u00e9o l\u00e0 g\u00ec, \u0110\u1ec1 ra k\u00e9p \u0111\u00e1nh l\u00f4 g\u00ec chu\u1ea9n nh\u1ea5t th\u00ec h\u1ed9i vi\u00ean c\u00f3 th\u1ec3 t\u00ecm hi\u1ec3u th\u00eam b\u00e0i vi\u1ebft<\/p>\n
<\/p>\n
1. Nu\u00f4i l\u00f4 k\u00e9p theo khung ng\u00e0y\u00a0l\u00e0 g\u00ec?<\/strong><\/h2>\nThu\u1eadt ng\u1eef nu\u00f4i l\u00f4 k\u00e9p theo khung\u00a0ng\u00e0y ch\u00ednh l\u00e0 vi\u1ec7c ch\u1ecdn ra 1 ho\u1eb7c nhi\u1ec1u b\u1ed9 l\u00f4 k\u00e9p \u0111\u1ec3 nu\u00f4i trong 2, 3, 5 ho\u1eb7c 7\u00a0ng\u00e0y k\u1ebf ti\u1ebfp nhau, v\u1edbi s\u1ed1 ti\u1ec1n ch\u01a1i th\u00edch h\u1ee3p \u0111\u1ec3 \u0111\u1ea3m b\u1ea3o lu\u00f4n c\u00f3 l\u1ee3i nhu\u1eadn khi l\u00f4 ra.<\/p>\n
Ng\u01b0\u1eddi ch\u01a1i c\u1ea7n ch\u00fa \u00fd n\u1ebfu k\u00e9p n\u1ed5 v\u00e0o ng\u00e0y 1 th\u00ec h\u00e3y h\u1ee7y lu\u00f4n b\u1ed9 s\u1ed1 k\u00e9p \u0111\u00f3 ch\u1ee9 kh\u00f4ng n\u00ean nu\u00f4i ti\u1ebfp v\u00e0o ng\u00e0y ti\u1ebfp theo v\u00ec c\u01a1 h\u1ed9i n\u1ed5 ti\u1ebfp s\u1ebd c\u1ef1c k\u1ef3 th\u1ea5p. L\u1eddi khuy\u00ean \u0111\u01b0a ra l\u00e0 ng\u01b0\u1eddi ch\u01a1i h\u00e3y nghi\u00ean c\u1ee9u 1 con l\u00f4 kh\u00e1c \u0111\u1ec3 nu\u00f4i.<\/p>\n
2. V\u00ec sao n\u00ean nu\u00f4i l\u00f4 k\u00e9p theo khung ng\u00e0y?<\/strong><\/h2>\nNu\u00f4i l\u00f4 k\u00e9p th\u01b0\u1eddng ph\u1ed5 bi\u1ebfn \u1edf c\u00e1c khung 2 ng\u00e0y, 3 ng\u00e0y,\u00a0 5 ng\u00e0y v\u00e0 7 ng\u00e0y.\u00a0Nhi\u1ec1u d\u00e2n ch\u01a1i l\u00f4 \u0111\u1ec1 cho r\u1eb1ng vi\u1ec7c nu\u00f4i l\u00f4 k\u00e9p theo khung ng\u00e0y l\u00e0 chi\u1ebfn thu\u1eadt hay nh\u1ea5t, t\u1ef7 l\u1ec7 th\u1eafng cao. Tuy nhi\u00ean, \u0111\u00f3 ho\u00e0n to\u00e0n kh\u00f4ng h\u1ec1 chu\u1ea9n x\u00e1c. Ngo\u00e0i nh\u1eefng \u01b0u \u0111i\u1ec3m, c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p n\u00e0y c\u00f2n t\u1ed3n t\u1ea1i m\u1ed9t v\u00e0i h\u1ea1n ch\u1ebf c\u1ea7n kh\u1eafc ph\u1ee5c.<\/p>\n
\u01afu \u0111i\u1ec3m<\/em><\/strong><\/h3>\n\n- Ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 k\u00e9p gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u0103ng hi\u1ec7u qu\u1ea3 \u0111\u1ea7u t\u01b0. B\u1ea1n s\u1ebd kh\u00f4ng c\u00f2n ph\u1ea3i th\u01b0\u1eddng xuy\u00ean g\u1eb7p c\u1ea3nh t\u01b0\u1ee3ng tr\u1edb tr\u00eau nay \u0111\u00e1nh nay mai m\u1edbi v\u1ec1, gi\u00fap ng\u01b0\u1eddi ch\u01a1i y\u00eau th\u00edch l\u1ed1i ch\u01a1i nu\u00f4i khung thay v\u00ec \u0111\u00e1nh theo ng\u00e0y.<\/li>\n
- Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ee7 \u0111\u1ed9ng v\u1ec1 v\u1ed1n \u0111\u1ec3 nu\u00f4i theo c\u00e1c khung ng\u00e0y \u0111\u00e3 \u0111\u1ecbnh t\u1eeb tr\u01b0\u1edbc.<\/li>\n
- Ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 k\u00e9p gi\u00fap ti\u1ebft ki\u1ec7m th\u1eddi gian nh\u1ea5t trong qu\u00e1 tr\u00ecnh soi c\u1ea7u. N\u1ebfu \u0111\u1ec1 kh\u00f4ng v\u1ec1 ng\u00e0y 1 th\u00ec ph\u1ea3i sau 2 ng\u00e0y b\u1ea1n m\u1edbi l\u1ea1i ph\u1ea3i v\u00f2 \u0111\u1ea7u t\u00ednh to\u00e1n ti\u1ebfp.<\/li>\n<\/ul>\n
H\u1ea1n ch\u1ebf<\/em><\/strong><\/h3>\nTh\u1ef1c ra ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 k\u00e9p khung ng\u00e0y t\u1ed3n t\u1ea1i kh\u00f4ng nhi\u1ec1u h\u1ea1n ch\u1ebf, ch\u1ec9 t\u1eadp trung \u1edf v\u1ed1n. N\u1ebfu ch\u01a1i nu\u00f4i l\u00f4 k\u00e9p th\u00ec b\u1ea1n c\u1ea7n chu\u1ea9n b\u1ecb m\u1ed9t ch\u00fat v\u1ed1n \u0111\u1ee7 l\u1edbn, c\u1ed9ng th\u00eam nh\u1eefng khung d\u1ef1 ph\u00f2ng kh\u00e1c. Nh\u1eefng ng\u01b0\u1eddi h\u01a1i \u00edt v\u1ed1n th\u00ec kh\u00f4ng n\u00ean ch\u1ecdn c\u00e1ch ch\u01a1i n\u00e0y.<\/p>\n
3. Chi ti\u1ebft c\u00e1ch v\u00e0o ti\u1ec1n l\u00f4 k\u00e9p khung c\u00e1c\u00a0ng\u00e0y<\/strong><\/h2>\nL\u01b0u \u00fd khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 2 ng\u00e0y<\/em><\/h3>\nC\u00e1ch v\u00e0o ti\u1ec1n chu\u1ea9n s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i c\u1eadp b\u1ebfn an to\u00e0n. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 c\u00e1c m\u1ee9c ti\u1ec1n gi\u00fap ng\u01b0\u1eddi ch\u01a1i lu\u00f4n c\u00f3 l\u1ee3i nhu\u1eadn d\u00f9 l\u00f4 k\u00e9p v\u1ec1 v\u00e0o ng\u00e0y cu\u1ed1i c\u00f9ng trong khung nu\u00f4i.<\/p>\n
C\u00e1ch v\u00e0o ti\u1ec1n ti\u1ec1n B\u1ea1ch th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y<\/p>\n
\u1ede \u0111\u00e2y, quy t\u1eafc l\u00e0 ti\u1ec1n v\u00e0o ng\u00e0y sau ph\u1ea3i g\u1ea5p \u0111\u00f4i, g\u1ea5p ba l\u1ea7n ng\u00e0y tr\u01b0\u1edbc.<\/p>\n
V\u00ed d\u1ee5:<\/p>\n
\n- Ng\u00e0y th\u1ee9 nh\u1ea5t, b\u1ea1n \u0111\u00e1nh 10 \u0111i\u1ec3m v\u00e0 v\u00e0o 100 ngh\u00ecn. N\u1ebfu ng\u00e0y 1 v\u1ec1 1 nh\u00e1y, b\u1ea1n l\u00e3i: 600 \u2013 100 = 500 ngh\u00ecn. N\u1ebfu kh\u00f4ng ra th\u00ec ch\u01a1i ti\u1ebfp v\u00e0o ng\u00e0y th\u1ee9 2.<\/li>\n
- Ng\u00e0y th\u1ee9 2, b\u1ea1n \u0111\u00e1nh 20 \u0111i\u1ec3m th\u00ec h\u1ebft 200 ngh\u00ecn. N\u1ebfu ra 1 nh\u00e1y th\u00ec l\u00e3i l\u00e0: 1.800 \u2013 (200+100) = 1.500 ngh\u00ecn.<\/li>\n<\/ul>\n
C\u00e1ch v\u00e0o ti\u1ec1n Song th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y:\u00a0V\u1edbi c\u00e1ch ch\u01a1i song th\u1ee7 l\u00f4 k\u00e9p, b\u1ea1n s\u1ebd c\u1ea7n s\u1ed1 v\u1ed1n nhi\u1ec1u h\u01a1n m\u1ed9t ch\u00fat. T\u1ef7 l\u1ec7 t\u1ed1t nh\u1ea5t \u0111\u1ec3 ch\u01a1i ch\u00ednh l\u00e0 1:3, 1:5.<\/p>\n
<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 3\u00a0ng\u00e0y<\/em><\/h3>\nV\u1edbi khung 3 ng\u00e0y, n\u1ebfu 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e8 k\u00e9p, \u0111\u00e2y l\u00e0 d\u1ea5u hi\u1ec7u s\u1ebd c\u00f3 k\u00e9p v\u1ec1 trong 1 tu\u1ea7n ti\u1ebfp theo. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn con l\u00f4 n\u00e0y \u0111\u1ec3 nu\u00f4i khungg 3 ng\u00e0y. T\u1ef7 l\u1ec7 \u0103n s\u1ebd r\u1ea5t cao.
\nN\u1ebfu s\u1ed1 \u0111\u1ea7u ho\u1eb7c 2 s\u1ed1 li\u1ec1n nhau c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 k\u00e9p th\u00ec k\u00e9p s\u1eafp v\u1ec1. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn s\u1ed1 n\u00e0y nu\u00f4i khung 2 hay 3 ng\u00e0y \u0111\u1ec3u d\u1ec5 h\u00fap.
\nT\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n c\u00f3 th\u1ec3 xem nh\u01b0 khung 2 ng\u00e0y b\u00ean tr\u00ean.<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 5\u00a0ng\u00e0y v\u00e0\u00a0l\u00f4 k\u00e9p nu\u00f4i khung 7 ng\u00e0y<\/em><\/h3>\nL\u00f4 k\u00e9p nu\u00f4i khung 5 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i an to\u00e0n, v\u1ed1n tr\u01b0\u1eddng, ch\u00ednh v\u00ec th\u1ebf t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n l\u00e0 \u0111i\u1ec1u h\u1ed9i vi\u00ean c\u1ea7n l\u01b0u \u00fd. \u00a0T\u1ef7 l\u1ec7 v\u1ed1n chia theo ng\u00e0y \u0111\u01b0\u1ee3c khuy\u00ean d\u00f9ng l\u00e0 1.2.4.6.8.
\nKhung 5 ng\u00e0y v\u00e0 khung ng\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng \u0111\u1ec3 nu\u00f4i l\u00f4 k\u00e9p b\u1ea1ch th\u1ee7. B\u1edfi h\u1ea1n ch\u1ebf v\u1ec1 v\u1ed1n v\u00e0 t\u0103ng l\u00e3i n\u00ean ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng s\u1eed d\u1ee5ng 1 con l\u00f4 v\u1edbi ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i tr\u01b0\u1eddng n\u00e0y.
\nNgo\u00e0i ra, c\u00f2n c\u00f3 m\u1ed9t v\u00e0i c\u1ea7u k\u00e9p \u0111\u1ec3 nu\u00f4i l\u00f4 khung 5 ng\u00e0y v\u00e0 7 ng\u00e0y hi\u1ec7u qu\u1ea3 m\u00e0 anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng nh\u01b0 sau:
\nGi\u1ea3i \u0111\u1eb7c bi\u1ec7t b\u1ec1 2 s\u1ed1 c\u00f3 k\u00e9p th\u00ec d\u00f9ng con \u0111\u00f3 \u0111\u1ec3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.
\n\u0110\u1eb7c bi\u1ec7t n\u1ed5 k\u00e9p l\u1ec7ch h\u1ed9i vi\u00ean c\u00f3 th\u1ec3 d\u00f9ng k\u00e9p \u0111\u00f3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.<\/p>\n
Tr\u00ean \u0111\u00e2y,\u00a0\u0111\u00e3 chia s\u1ebb \u0111\u1ebfn b\u1ea1n \u0111\u1ecdc nh\u1eefng\u00a0c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p khung 2 ng\u00e0y\u00a0v\u00e0 c\u00e1c th\u00f4ng tin h\u1eefu \u00edch xoay quanh l\u00f4 k\u00e9p 2 ng\u00e0y. Mong r\u1eb1ng b\u00e0i vi\u1ebft s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u1ef1 tin h\u01a1n v\u1edbi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p l\u00f4 \u0111\u1ec1!<\/p>\n<\/div>\n<\/div>\n
chuy\u00ean gia ch\u1ed1t s\u1ed1 v\u00edp si\u00eau h\u00f3t<\/strong><\/span><\/h3>\n\n
Nu\u00f4i l\u00f4 k\u00e9p th\u01b0\u1eddng ph\u1ed5 bi\u1ebfn \u1edf c\u00e1c khung 2 ng\u00e0y, 3 ng\u00e0y,\u00a0 5 ng\u00e0y v\u00e0 7 ng\u00e0y.\u00a0Nhi\u1ec1u d\u00e2n ch\u01a1i l\u00f4 \u0111\u1ec1 cho r\u1eb1ng vi\u1ec7c nu\u00f4i l\u00f4 k\u00e9p theo khung ng\u00e0y l\u00e0 chi\u1ebfn thu\u1eadt hay nh\u1ea5t, t\u1ef7 l\u1ec7 th\u1eafng cao. Tuy nhi\u00ean, \u0111\u00f3 ho\u00e0n to\u00e0n kh\u00f4ng h\u1ec1 chu\u1ea9n x\u00e1c. Ngo\u00e0i nh\u1eefng \u01b0u \u0111i\u1ec3m, c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p n\u00e0y c\u00f2n t\u1ed3n t\u1ea1i m\u1ed9t v\u00e0i h\u1ea1n ch\u1ebf c\u1ea7n kh\u1eafc ph\u1ee5c.<\/p>\n
\u01afu \u0111i\u1ec3m<\/em><\/strong><\/h3>\n\n- Ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 k\u00e9p gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u0103ng hi\u1ec7u qu\u1ea3 \u0111\u1ea7u t\u01b0. B\u1ea1n s\u1ebd kh\u00f4ng c\u00f2n ph\u1ea3i th\u01b0\u1eddng xuy\u00ean g\u1eb7p c\u1ea3nh t\u01b0\u1ee3ng tr\u1edb tr\u00eau nay \u0111\u00e1nh nay mai m\u1edbi v\u1ec1, gi\u00fap ng\u01b0\u1eddi ch\u01a1i y\u00eau th\u00edch l\u1ed1i ch\u01a1i nu\u00f4i khung thay v\u00ec \u0111\u00e1nh theo ng\u00e0y.<\/li>\n
- Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ee7 \u0111\u1ed9ng v\u1ec1 v\u1ed1n \u0111\u1ec3 nu\u00f4i theo c\u00e1c khung ng\u00e0y \u0111\u00e3 \u0111\u1ecbnh t\u1eeb tr\u01b0\u1edbc.<\/li>\n
- Ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 k\u00e9p gi\u00fap ti\u1ebft ki\u1ec7m th\u1eddi gian nh\u1ea5t trong qu\u00e1 tr\u00ecnh soi c\u1ea7u. N\u1ebfu \u0111\u1ec1 kh\u00f4ng v\u1ec1 ng\u00e0y 1 th\u00ec ph\u1ea3i sau 2 ng\u00e0y b\u1ea1n m\u1edbi l\u1ea1i ph\u1ea3i v\u00f2 \u0111\u1ea7u t\u00ednh to\u00e1n ti\u1ebfp.<\/li>\n<\/ul>\n
H\u1ea1n ch\u1ebf<\/em><\/strong><\/h3>\nTh\u1ef1c ra ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 k\u00e9p khung ng\u00e0y t\u1ed3n t\u1ea1i kh\u00f4ng nhi\u1ec1u h\u1ea1n ch\u1ebf, ch\u1ec9 t\u1eadp trung \u1edf v\u1ed1n. N\u1ebfu ch\u01a1i nu\u00f4i l\u00f4 k\u00e9p th\u00ec b\u1ea1n c\u1ea7n chu\u1ea9n b\u1ecb m\u1ed9t ch\u00fat v\u1ed1n \u0111\u1ee7 l\u1edbn, c\u1ed9ng th\u00eam nh\u1eefng khung d\u1ef1 ph\u00f2ng kh\u00e1c. Nh\u1eefng ng\u01b0\u1eddi h\u01a1i \u00edt v\u1ed1n th\u00ec kh\u00f4ng n\u00ean ch\u1ecdn c\u00e1ch ch\u01a1i n\u00e0y.<\/p>\n
3. Chi ti\u1ebft c\u00e1ch v\u00e0o ti\u1ec1n l\u00f4 k\u00e9p khung c\u00e1c\u00a0ng\u00e0y<\/strong><\/h2>\nL\u01b0u \u00fd khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 2 ng\u00e0y<\/em><\/h3>\nC\u00e1ch v\u00e0o ti\u1ec1n chu\u1ea9n s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i c\u1eadp b\u1ebfn an to\u00e0n. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 c\u00e1c m\u1ee9c ti\u1ec1n gi\u00fap ng\u01b0\u1eddi ch\u01a1i lu\u00f4n c\u00f3 l\u1ee3i nhu\u1eadn d\u00f9 l\u00f4 k\u00e9p v\u1ec1 v\u00e0o ng\u00e0y cu\u1ed1i c\u00f9ng trong khung nu\u00f4i.<\/p>\n
C\u00e1ch v\u00e0o ti\u1ec1n ti\u1ec1n B\u1ea1ch th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y<\/p>\n
\u1ede \u0111\u00e2y, quy t\u1eafc l\u00e0 ti\u1ec1n v\u00e0o ng\u00e0y sau ph\u1ea3i g\u1ea5p \u0111\u00f4i, g\u1ea5p ba l\u1ea7n ng\u00e0y tr\u01b0\u1edbc.<\/p>\n
V\u00ed d\u1ee5:<\/p>\n
\n- Ng\u00e0y th\u1ee9 nh\u1ea5t, b\u1ea1n \u0111\u00e1nh 10 \u0111i\u1ec3m v\u00e0 v\u00e0o 100 ngh\u00ecn. N\u1ebfu ng\u00e0y 1 v\u1ec1 1 nh\u00e1y, b\u1ea1n l\u00e3i: 600 \u2013 100 = 500 ngh\u00ecn. N\u1ebfu kh\u00f4ng ra th\u00ec ch\u01a1i ti\u1ebfp v\u00e0o ng\u00e0y th\u1ee9 2.<\/li>\n
- Ng\u00e0y th\u1ee9 2, b\u1ea1n \u0111\u00e1nh 20 \u0111i\u1ec3m th\u00ec h\u1ebft 200 ngh\u00ecn. N\u1ebfu ra 1 nh\u00e1y th\u00ec l\u00e3i l\u00e0: 1.800 \u2013 (200+100) = 1.500 ngh\u00ecn.<\/li>\n<\/ul>\n
C\u00e1ch v\u00e0o ti\u1ec1n Song th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y:\u00a0V\u1edbi c\u00e1ch ch\u01a1i song th\u1ee7 l\u00f4 k\u00e9p, b\u1ea1n s\u1ebd c\u1ea7n s\u1ed1 v\u1ed1n nhi\u1ec1u h\u01a1n m\u1ed9t ch\u00fat. T\u1ef7 l\u1ec7 t\u1ed1t nh\u1ea5t \u0111\u1ec3 ch\u01a1i ch\u00ednh l\u00e0 1:3, 1:5.<\/p>\n
<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 3\u00a0ng\u00e0y<\/em><\/h3>\nV\u1edbi khung 3 ng\u00e0y, n\u1ebfu 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e8 k\u00e9p, \u0111\u00e2y l\u00e0 d\u1ea5u hi\u1ec7u s\u1ebd c\u00f3 k\u00e9p v\u1ec1 trong 1 tu\u1ea7n ti\u1ebfp theo. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn con l\u00f4 n\u00e0y \u0111\u1ec3 nu\u00f4i khungg 3 ng\u00e0y. T\u1ef7 l\u1ec7 \u0103n s\u1ebd r\u1ea5t cao.
\nN\u1ebfu s\u1ed1 \u0111\u1ea7u ho\u1eb7c 2 s\u1ed1 li\u1ec1n nhau c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 k\u00e9p th\u00ec k\u00e9p s\u1eafp v\u1ec1. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn s\u1ed1 n\u00e0y nu\u00f4i khung 2 hay 3 ng\u00e0y \u0111\u1ec3u d\u1ec5 h\u00fap.
\nT\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n c\u00f3 th\u1ec3 xem nh\u01b0 khung 2 ng\u00e0y b\u00ean tr\u00ean.<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 5\u00a0ng\u00e0y v\u00e0\u00a0l\u00f4 k\u00e9p nu\u00f4i khung 7 ng\u00e0y<\/em><\/h3>\nL\u00f4 k\u00e9p nu\u00f4i khung 5 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i an to\u00e0n, v\u1ed1n tr\u01b0\u1eddng, ch\u00ednh v\u00ec th\u1ebf t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n l\u00e0 \u0111i\u1ec1u h\u1ed9i vi\u00ean c\u1ea7n l\u01b0u \u00fd. \u00a0T\u1ef7 l\u1ec7 v\u1ed1n chia theo ng\u00e0y \u0111\u01b0\u1ee3c khuy\u00ean d\u00f9ng l\u00e0 1.2.4.6.8.
\nKhung 5 ng\u00e0y v\u00e0 khung ng\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng \u0111\u1ec3 nu\u00f4i l\u00f4 k\u00e9p b\u1ea1ch th\u1ee7. B\u1edfi h\u1ea1n ch\u1ebf v\u1ec1 v\u1ed1n v\u00e0 t\u0103ng l\u00e3i n\u00ean ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng s\u1eed d\u1ee5ng 1 con l\u00f4 v\u1edbi ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i tr\u01b0\u1eddng n\u00e0y.
\nNgo\u00e0i ra, c\u00f2n c\u00f3 m\u1ed9t v\u00e0i c\u1ea7u k\u00e9p \u0111\u1ec3 nu\u00f4i l\u00f4 khung 5 ng\u00e0y v\u00e0 7 ng\u00e0y hi\u1ec7u qu\u1ea3 m\u00e0 anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng nh\u01b0 sau:
\nGi\u1ea3i \u0111\u1eb7c bi\u1ec7t b\u1ec1 2 s\u1ed1 c\u00f3 k\u00e9p th\u00ec d\u00f9ng con \u0111\u00f3 \u0111\u1ec3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.
\n\u0110\u1eb7c bi\u1ec7t n\u1ed5 k\u00e9p l\u1ec7ch h\u1ed9i vi\u00ean c\u00f3 th\u1ec3 d\u00f9ng k\u00e9p \u0111\u00f3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.<\/p>\n
Tr\u00ean \u0111\u00e2y,\u00a0\u0111\u00e3 chia s\u1ebb \u0111\u1ebfn b\u1ea1n \u0111\u1ecdc nh\u1eefng\u00a0c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p khung 2 ng\u00e0y\u00a0v\u00e0 c\u00e1c th\u00f4ng tin h\u1eefu \u00edch xoay quanh l\u00f4 k\u00e9p 2 ng\u00e0y. Mong r\u1eb1ng b\u00e0i vi\u1ebft s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u1ef1 tin h\u01a1n v\u1edbi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p l\u00f4 \u0111\u1ec1!<\/p>\n<\/div>\n<\/div>\n
chuy\u00ean gia ch\u1ed1t s\u1ed1 v\u00edp si\u00eau h\u00f3t<\/strong><\/span><\/h3>\n\n
H\u1ea1n ch\u1ebf<\/em><\/strong><\/h3>\nTh\u1ef1c ra ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i l\u00f4 k\u00e9p khung ng\u00e0y t\u1ed3n t\u1ea1i kh\u00f4ng nhi\u1ec1u h\u1ea1n ch\u1ebf, ch\u1ec9 t\u1eadp trung \u1edf v\u1ed1n. N\u1ebfu ch\u01a1i nu\u00f4i l\u00f4 k\u00e9p th\u00ec b\u1ea1n c\u1ea7n chu\u1ea9n b\u1ecb m\u1ed9t ch\u00fat v\u1ed1n \u0111\u1ee7 l\u1edbn, c\u1ed9ng th\u00eam nh\u1eefng khung d\u1ef1 ph\u00f2ng kh\u00e1c. Nh\u1eefng ng\u01b0\u1eddi h\u01a1i \u00edt v\u1ed1n th\u00ec kh\u00f4ng n\u00ean ch\u1ecdn c\u00e1ch ch\u01a1i n\u00e0y.<\/p>\n
3. Chi ti\u1ebft c\u00e1ch v\u00e0o ti\u1ec1n l\u00f4 k\u00e9p khung c\u00e1c\u00a0ng\u00e0y<\/strong><\/h2>\nL\u01b0u \u00fd khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 2 ng\u00e0y<\/em><\/h3>\nC\u00e1ch v\u00e0o ti\u1ec1n chu\u1ea9n s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i c\u1eadp b\u1ebfn an to\u00e0n. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 c\u00e1c m\u1ee9c ti\u1ec1n gi\u00fap ng\u01b0\u1eddi ch\u01a1i lu\u00f4n c\u00f3 l\u1ee3i nhu\u1eadn d\u00f9 l\u00f4 k\u00e9p v\u1ec1 v\u00e0o ng\u00e0y cu\u1ed1i c\u00f9ng trong khung nu\u00f4i.<\/p>\n
C\u00e1ch v\u00e0o ti\u1ec1n ti\u1ec1n B\u1ea1ch th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y<\/p>\n
\u1ede \u0111\u00e2y, quy t\u1eafc l\u00e0 ti\u1ec1n v\u00e0o ng\u00e0y sau ph\u1ea3i g\u1ea5p \u0111\u00f4i, g\u1ea5p ba l\u1ea7n ng\u00e0y tr\u01b0\u1edbc.<\/p>\n
V\u00ed d\u1ee5:<\/p>\n
\n- Ng\u00e0y th\u1ee9 nh\u1ea5t, b\u1ea1n \u0111\u00e1nh 10 \u0111i\u1ec3m v\u00e0 v\u00e0o 100 ngh\u00ecn. N\u1ebfu ng\u00e0y 1 v\u1ec1 1 nh\u00e1y, b\u1ea1n l\u00e3i: 600 \u2013 100 = 500 ngh\u00ecn. N\u1ebfu kh\u00f4ng ra th\u00ec ch\u01a1i ti\u1ebfp v\u00e0o ng\u00e0y th\u1ee9 2.<\/li>\n
- Ng\u00e0y th\u1ee9 2, b\u1ea1n \u0111\u00e1nh 20 \u0111i\u1ec3m th\u00ec h\u1ebft 200 ngh\u00ecn. N\u1ebfu ra 1 nh\u00e1y th\u00ec l\u00e3i l\u00e0: 1.800 \u2013 (200+100) = 1.500 ngh\u00ecn.<\/li>\n<\/ul>\n
C\u00e1ch v\u00e0o ti\u1ec1n Song th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y:\u00a0V\u1edbi c\u00e1ch ch\u01a1i song th\u1ee7 l\u00f4 k\u00e9p, b\u1ea1n s\u1ebd c\u1ea7n s\u1ed1 v\u1ed1n nhi\u1ec1u h\u01a1n m\u1ed9t ch\u00fat. T\u1ef7 l\u1ec7 t\u1ed1t nh\u1ea5t \u0111\u1ec3 ch\u01a1i ch\u00ednh l\u00e0 1:3, 1:5.<\/p>\n
<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 3\u00a0ng\u00e0y<\/em><\/h3>\nV\u1edbi khung 3 ng\u00e0y, n\u1ebfu 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e8 k\u00e9p, \u0111\u00e2y l\u00e0 d\u1ea5u hi\u1ec7u s\u1ebd c\u00f3 k\u00e9p v\u1ec1 trong 1 tu\u1ea7n ti\u1ebfp theo. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn con l\u00f4 n\u00e0y \u0111\u1ec3 nu\u00f4i khungg 3 ng\u00e0y. T\u1ef7 l\u1ec7 \u0103n s\u1ebd r\u1ea5t cao.
\nN\u1ebfu s\u1ed1 \u0111\u1ea7u ho\u1eb7c 2 s\u1ed1 li\u1ec1n nhau c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 k\u00e9p th\u00ec k\u00e9p s\u1eafp v\u1ec1. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn s\u1ed1 n\u00e0y nu\u00f4i khung 2 hay 3 ng\u00e0y \u0111\u1ec3u d\u1ec5 h\u00fap.
\nT\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n c\u00f3 th\u1ec3 xem nh\u01b0 khung 2 ng\u00e0y b\u00ean tr\u00ean.<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 5\u00a0ng\u00e0y v\u00e0\u00a0l\u00f4 k\u00e9p nu\u00f4i khung 7 ng\u00e0y<\/em><\/h3>\nL\u00f4 k\u00e9p nu\u00f4i khung 5 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i an to\u00e0n, v\u1ed1n tr\u01b0\u1eddng, ch\u00ednh v\u00ec th\u1ebf t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n l\u00e0 \u0111i\u1ec1u h\u1ed9i vi\u00ean c\u1ea7n l\u01b0u \u00fd. \u00a0T\u1ef7 l\u1ec7 v\u1ed1n chia theo ng\u00e0y \u0111\u01b0\u1ee3c khuy\u00ean d\u00f9ng l\u00e0 1.2.4.6.8.
\nKhung 5 ng\u00e0y v\u00e0 khung ng\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng \u0111\u1ec3 nu\u00f4i l\u00f4 k\u00e9p b\u1ea1ch th\u1ee7. B\u1edfi h\u1ea1n ch\u1ebf v\u1ec1 v\u1ed1n v\u00e0 t\u0103ng l\u00e3i n\u00ean ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng s\u1eed d\u1ee5ng 1 con l\u00f4 v\u1edbi ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i tr\u01b0\u1eddng n\u00e0y.
\nNgo\u00e0i ra, c\u00f2n c\u00f3 m\u1ed9t v\u00e0i c\u1ea7u k\u00e9p \u0111\u1ec3 nu\u00f4i l\u00f4 khung 5 ng\u00e0y v\u00e0 7 ng\u00e0y hi\u1ec7u qu\u1ea3 m\u00e0 anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng nh\u01b0 sau:
\nGi\u1ea3i \u0111\u1eb7c bi\u1ec7t b\u1ec1 2 s\u1ed1 c\u00f3 k\u00e9p th\u00ec d\u00f9ng con \u0111\u00f3 \u0111\u1ec3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.
\n\u0110\u1eb7c bi\u1ec7t n\u1ed5 k\u00e9p l\u1ec7ch h\u1ed9i vi\u00ean c\u00f3 th\u1ec3 d\u00f9ng k\u00e9p \u0111\u00f3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.<\/p>\n
Tr\u00ean \u0111\u00e2y,\u00a0\u0111\u00e3 chia s\u1ebb \u0111\u1ebfn b\u1ea1n \u0111\u1ecdc nh\u1eefng\u00a0c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p khung 2 ng\u00e0y\u00a0v\u00e0 c\u00e1c th\u00f4ng tin h\u1eefu \u00edch xoay quanh l\u00f4 k\u00e9p 2 ng\u00e0y. Mong r\u1eb1ng b\u00e0i vi\u1ebft s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u1ef1 tin h\u01a1n v\u1edbi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p l\u00f4 \u0111\u1ec1!<\/p>\n<\/div>\n<\/div>\n
chuy\u00ean gia ch\u1ed1t s\u1ed1 v\u00edp si\u00eau h\u00f3t<\/strong><\/span><\/h3>\n\n
L\u01b0u \u00fd khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 2 ng\u00e0y<\/em><\/h3>\nC\u00e1ch v\u00e0o ti\u1ec1n chu\u1ea9n s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i c\u1eadp b\u1ebfn an to\u00e0n. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 c\u00e1c m\u1ee9c ti\u1ec1n gi\u00fap ng\u01b0\u1eddi ch\u01a1i lu\u00f4n c\u00f3 l\u1ee3i nhu\u1eadn d\u00f9 l\u00f4 k\u00e9p v\u1ec1 v\u00e0o ng\u00e0y cu\u1ed1i c\u00f9ng trong khung nu\u00f4i.<\/p>\n
C\u00e1ch v\u00e0o ti\u1ec1n ti\u1ec1n B\u1ea1ch th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y<\/p>\n
\u1ede \u0111\u00e2y, quy t\u1eafc l\u00e0 ti\u1ec1n v\u00e0o ng\u00e0y sau ph\u1ea3i g\u1ea5p \u0111\u00f4i, g\u1ea5p ba l\u1ea7n ng\u00e0y tr\u01b0\u1edbc.<\/p>\n
V\u00ed d\u1ee5:<\/p>\n
\n- Ng\u00e0y th\u1ee9 nh\u1ea5t, b\u1ea1n \u0111\u00e1nh 10 \u0111i\u1ec3m v\u00e0 v\u00e0o 100 ngh\u00ecn. N\u1ebfu ng\u00e0y 1 v\u1ec1 1 nh\u00e1y, b\u1ea1n l\u00e3i: 600 \u2013 100 = 500 ngh\u00ecn. N\u1ebfu kh\u00f4ng ra th\u00ec ch\u01a1i ti\u1ebfp v\u00e0o ng\u00e0y th\u1ee9 2.<\/li>\n
- Ng\u00e0y th\u1ee9 2, b\u1ea1n \u0111\u00e1nh 20 \u0111i\u1ec3m th\u00ec h\u1ebft 200 ngh\u00ecn. N\u1ebfu ra 1 nh\u00e1y th\u00ec l\u00e3i l\u00e0: 1.800 \u2013 (200+100) = 1.500 ngh\u00ecn.<\/li>\n<\/ul>\n
C\u00e1ch v\u00e0o ti\u1ec1n Song th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y:\u00a0V\u1edbi c\u00e1ch ch\u01a1i song th\u1ee7 l\u00f4 k\u00e9p, b\u1ea1n s\u1ebd c\u1ea7n s\u1ed1 v\u1ed1n nhi\u1ec1u h\u01a1n m\u1ed9t ch\u00fat. T\u1ef7 l\u1ec7 t\u1ed1t nh\u1ea5t \u0111\u1ec3 ch\u01a1i ch\u00ednh l\u00e0 1:3, 1:5.<\/p>\n
<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 3\u00a0ng\u00e0y<\/em><\/h3>\nV\u1edbi khung 3 ng\u00e0y, n\u1ebfu 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e8 k\u00e9p, \u0111\u00e2y l\u00e0 d\u1ea5u hi\u1ec7u s\u1ebd c\u00f3 k\u00e9p v\u1ec1 trong 1 tu\u1ea7n ti\u1ebfp theo. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn con l\u00f4 n\u00e0y \u0111\u1ec3 nu\u00f4i khungg 3 ng\u00e0y. T\u1ef7 l\u1ec7 \u0103n s\u1ebd r\u1ea5t cao.
\nN\u1ebfu s\u1ed1 \u0111\u1ea7u ho\u1eb7c 2 s\u1ed1 li\u1ec1n nhau c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 k\u00e9p th\u00ec k\u00e9p s\u1eafp v\u1ec1. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn s\u1ed1 n\u00e0y nu\u00f4i khung 2 hay 3 ng\u00e0y \u0111\u1ec3u d\u1ec5 h\u00fap.
\nT\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n c\u00f3 th\u1ec3 xem nh\u01b0 khung 2 ng\u00e0y b\u00ean tr\u00ean.<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 5\u00a0ng\u00e0y v\u00e0\u00a0l\u00f4 k\u00e9p nu\u00f4i khung 7 ng\u00e0y<\/em><\/h3>\nL\u00f4 k\u00e9p nu\u00f4i khung 5 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i an to\u00e0n, v\u1ed1n tr\u01b0\u1eddng, ch\u00ednh v\u00ec th\u1ebf t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n l\u00e0 \u0111i\u1ec1u h\u1ed9i vi\u00ean c\u1ea7n l\u01b0u \u00fd. \u00a0T\u1ef7 l\u1ec7 v\u1ed1n chia theo ng\u00e0y \u0111\u01b0\u1ee3c khuy\u00ean d\u00f9ng l\u00e0 1.2.4.6.8.
\nKhung 5 ng\u00e0y v\u00e0 khung ng\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng \u0111\u1ec3 nu\u00f4i l\u00f4 k\u00e9p b\u1ea1ch th\u1ee7. B\u1edfi h\u1ea1n ch\u1ebf v\u1ec1 v\u1ed1n v\u00e0 t\u0103ng l\u00e3i n\u00ean ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng s\u1eed d\u1ee5ng 1 con l\u00f4 v\u1edbi ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i tr\u01b0\u1eddng n\u00e0y.
\nNgo\u00e0i ra, c\u00f2n c\u00f3 m\u1ed9t v\u00e0i c\u1ea7u k\u00e9p \u0111\u1ec3 nu\u00f4i l\u00f4 khung 5 ng\u00e0y v\u00e0 7 ng\u00e0y hi\u1ec7u qu\u1ea3 m\u00e0 anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng nh\u01b0 sau:
\nGi\u1ea3i \u0111\u1eb7c bi\u1ec7t b\u1ec1 2 s\u1ed1 c\u00f3 k\u00e9p th\u00ec d\u00f9ng con \u0111\u00f3 \u0111\u1ec3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.
\n\u0110\u1eb7c bi\u1ec7t n\u1ed5 k\u00e9p l\u1ec7ch h\u1ed9i vi\u00ean c\u00f3 th\u1ec3 d\u00f9ng k\u00e9p \u0111\u00f3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.<\/p>\n
Tr\u00ean \u0111\u00e2y,\u00a0\u0111\u00e3 chia s\u1ebb \u0111\u1ebfn b\u1ea1n \u0111\u1ecdc nh\u1eefng\u00a0c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p khung 2 ng\u00e0y\u00a0v\u00e0 c\u00e1c th\u00f4ng tin h\u1eefu \u00edch xoay quanh l\u00f4 k\u00e9p 2 ng\u00e0y. Mong r\u1eb1ng b\u00e0i vi\u1ebft s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u1ef1 tin h\u01a1n v\u1edbi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p l\u00f4 \u0111\u1ec1!<\/p>\n<\/div>\n<\/div>\n
chuy\u00ean gia ch\u1ed1t s\u1ed1 v\u00edp si\u00eau h\u00f3t<\/strong><\/span><\/h3>\n\n
C\u00e1ch v\u00e0o ti\u1ec1n Song th\u1ee7 l\u00f4 k\u00e9p khung 2 ng\u00e0y:\u00a0V\u1edbi c\u00e1ch ch\u01a1i song th\u1ee7 l\u00f4 k\u00e9p, b\u1ea1n s\u1ebd c\u1ea7n s\u1ed1 v\u1ed1n nhi\u1ec1u h\u01a1n m\u1ed9t ch\u00fat. T\u1ef7 l\u1ec7 t\u1ed1t nh\u1ea5t \u0111\u1ec3 ch\u01a1i ch\u00ednh l\u00e0 1:3, 1:5.<\/p>\n
<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 3\u00a0ng\u00e0y<\/em><\/h3>\nV\u1edbi khung 3 ng\u00e0y, n\u1ebfu 2 s\u1ed1 \u0111\u1ea7u c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e8 k\u00e9p, \u0111\u00e2y l\u00e0 d\u1ea5u hi\u1ec7u s\u1ebd c\u00f3 k\u00e9p v\u1ec1 trong 1 tu\u1ea7n ti\u1ebfp theo. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn con l\u00f4 n\u00e0y \u0111\u1ec3 nu\u00f4i khungg 3 ng\u00e0y. T\u1ef7 l\u1ec7 \u0103n s\u1ebd r\u1ea5t cao.
\nN\u1ebfu s\u1ed1 \u0111\u1ea7u ho\u1eb7c 2 s\u1ed1 li\u1ec1n nhau c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 k\u00e9p th\u00ec k\u00e9p s\u1eafp v\u1ec1. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn s\u1ed1 n\u00e0y nu\u00f4i khung 2 hay 3 ng\u00e0y \u0111\u1ec3u d\u1ec5 h\u00fap.
\nT\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n c\u00f3 th\u1ec3 xem nh\u01b0 khung 2 ng\u00e0y b\u00ean tr\u00ean.<\/p>\n
L\u01b0u \u00fd\u00a0khi ch\u01a1i l\u00f4 k\u00e9p nu\u00f4i khung 5\u00a0ng\u00e0y v\u00e0\u00a0l\u00f4 k\u00e9p nu\u00f4i khung 7 ng\u00e0y<\/em><\/h3>\nL\u00f4 k\u00e9p nu\u00f4i khung 5 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i an to\u00e0n, v\u1ed1n tr\u01b0\u1eddng, ch\u00ednh v\u00ec th\u1ebf t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n l\u00e0 \u0111i\u1ec1u h\u1ed9i vi\u00ean c\u1ea7n l\u01b0u \u00fd. \u00a0T\u1ef7 l\u1ec7 v\u1ed1n chia theo ng\u00e0y \u0111\u01b0\u1ee3c khuy\u00ean d\u00f9ng l\u00e0 1.2.4.6.8.
\nKhung 5 ng\u00e0y v\u00e0 khung ng\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng \u0111\u1ec3 nu\u00f4i l\u00f4 k\u00e9p b\u1ea1ch th\u1ee7. B\u1edfi h\u1ea1n ch\u1ebf v\u1ec1 v\u1ed1n v\u00e0 t\u0103ng l\u00e3i n\u00ean ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng s\u1eed d\u1ee5ng 1 con l\u00f4 v\u1edbi ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i tr\u01b0\u1eddng n\u00e0y.
\nNgo\u00e0i ra, c\u00f2n c\u00f3 m\u1ed9t v\u00e0i c\u1ea7u k\u00e9p \u0111\u1ec3 nu\u00f4i l\u00f4 khung 5 ng\u00e0y v\u00e0 7 ng\u00e0y hi\u1ec7u qu\u1ea3 m\u00e0 anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng nh\u01b0 sau:
\nGi\u1ea3i \u0111\u1eb7c bi\u1ec7t b\u1ec1 2 s\u1ed1 c\u00f3 k\u00e9p th\u00ec d\u00f9ng con \u0111\u00f3 \u0111\u1ec3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.
\n\u0110\u1eb7c bi\u1ec7t n\u1ed5 k\u00e9p l\u1ec7ch h\u1ed9i vi\u00ean c\u00f3 th\u1ec3 d\u00f9ng k\u00e9p \u0111\u00f3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.<\/p>\n
Tr\u00ean \u0111\u00e2y,\u00a0\u0111\u00e3 chia s\u1ebb \u0111\u1ebfn b\u1ea1n \u0111\u1ecdc nh\u1eefng\u00a0c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p khung 2 ng\u00e0y\u00a0v\u00e0 c\u00e1c th\u00f4ng tin h\u1eefu \u00edch xoay quanh l\u00f4 k\u00e9p 2 ng\u00e0y. Mong r\u1eb1ng b\u00e0i vi\u1ebft s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u1ef1 tin h\u01a1n v\u1edbi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p l\u00f4 \u0111\u1ec1!<\/p>\n<\/div>\n<\/div>\n
chuy\u00ean gia ch\u1ed1t s\u1ed1 v\u00edp si\u00eau h\u00f3t<\/strong><\/span><\/h3>\n\n
\nN\u1ebfu s\u1ed1 \u0111\u1ea7u ho\u1eb7c 2 s\u1ed1 li\u1ec1n nhau c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 k\u00e9p th\u00ec k\u00e9p s\u1eafp v\u1ec1. Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 ch\u1ecdn s\u1ed1 n\u00e0y nu\u00f4i khung 2 hay 3 ng\u00e0y \u0111\u1ec3u d\u1ec5 h\u00fap.
\nT\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n c\u00f3 th\u1ec3 xem nh\u01b0 khung 2 ng\u00e0y b\u00ean tr\u00ean.<\/p>\n
L\u00f4 k\u00e9p nu\u00f4i khung 5 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i an to\u00e0n, v\u1ed1n tr\u01b0\u1eddng, ch\u00ednh v\u00ec th\u1ebf t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n l\u00e0 \u0111i\u1ec1u h\u1ed9i vi\u00ean c\u1ea7n l\u01b0u \u00fd. \u00a0T\u1ef7 l\u1ec7 v\u1ed1n chia theo ng\u00e0y \u0111\u01b0\u1ee3c khuy\u00ean d\u00f9ng l\u00e0 1.2.4.6.8.
\nKhung 5 ng\u00e0y v\u00e0 khung ng\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng \u0111\u1ec3 nu\u00f4i l\u00f4 k\u00e9p b\u1ea1ch th\u1ee7. B\u1edfi h\u1ea1n ch\u1ebf v\u1ec1 v\u1ed1n v\u00e0 t\u0103ng l\u00e3i n\u00ean ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng s\u1eed d\u1ee5ng 1 con l\u00f4 v\u1edbi ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i tr\u01b0\u1eddng n\u00e0y.
\nNgo\u00e0i ra, c\u00f2n c\u00f3 m\u1ed9t v\u00e0i c\u1ea7u k\u00e9p \u0111\u1ec3 nu\u00f4i l\u00f4 khung 5 ng\u00e0y v\u00e0 7 ng\u00e0y hi\u1ec7u qu\u1ea3 m\u00e0 anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng nh\u01b0 sau:
\nGi\u1ea3i \u0111\u1eb7c bi\u1ec7t b\u1ec1 2 s\u1ed1 c\u00f3 k\u00e9p th\u00ec d\u00f9ng con \u0111\u00f3 \u0111\u1ec3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.
\n\u0110\u1eb7c bi\u1ec7t n\u1ed5 k\u00e9p l\u1ec7ch h\u1ed9i vi\u00ean c\u00f3 th\u1ec3 d\u00f9ng k\u00e9p \u0111\u00f3 nu\u00f4i 5 v\u00e0 7 ng\u00e0y.<\/p>\n
Tr\u00ean \u0111\u00e2y,\u00a0\u0111\u00e3 chia s\u1ebb \u0111\u1ebfn b\u1ea1n \u0111\u1ecdc nh\u1eefng\u00a0c\u00e1ch nu\u00f4i l\u00f4 k\u00e9p khung 2 ng\u00e0y\u00a0v\u00e0 c\u00e1c th\u00f4ng tin h\u1eefu \u00edch xoay quanh l\u00f4 k\u00e9p 2 ng\u00e0y. Mong r\u1eb1ng b\u00e0i vi\u1ebft s\u1ebd gi\u00fap ng\u01b0\u1eddi ch\u01a1i t\u1ef1 tin h\u01a1n v\u1edbi c\u00e1c ph\u01b0\u01a1ng ph\u00e1p l\u00f4 \u0111\u1ec1!<\/p>\n<\/div>\n<\/div>\n